Global International School
| Q.No | Answer | Explanation |
|---|---|---|
| 1. | (b) J.J. Thomson | J.J. Thomson is credited with the discovery of the electron. |
| 2. | (c) No charge | The neutron is a sub-atomic particle that possesses no electrical charge (it is neutral). |
| 3. | (b) 8 | The maximum number of electrons for a shell is 2n2. For L-shell (n=2): 2(22) = 8. |
| 4. | (c) Nucleus | Rutherford concluded that all positive charge and mass are concentrated in the central nucleus. |
| 5. | (b) Isobars | Isobars are atoms of different elements with different atomic numbers but the same mass number. |
| 6. | (c) 2000 times | The mass of a proton is approximately 2000 times the mass of an electron. |
| 7. | (b) Proton | The proton carries a positive charge (+1), equal in magnitude but opposite to the electron. |
| 8. | (c) 0 | Atoms with a completely filled outermost shell (octet) show little chemical activity, so valency is zero. |
| 9. | (c) Neutron | J. Chadwick discovered the neutron in 1932. |
| 10. | (c) 6 protons | Atomic Number (Z) is defined as the total number of protons in the nucleus. |
The maximum number of electrons in the L-shell (n=2) is 8.
Total electrons = 2 + 8 = 10.
A = 11 + 12 = 23.
Neutrons = 4 - 2 = 2 neutrons.
| Particle | Charge | Mass (Approx.) | Location |
|---|---|---|---|
| Electron | Negative (-1) | Negligible (1/2000 of p+) | Revolves around nucleus |
| Proton | Positive (+1) | 1 unit | Inside nucleus |
| Neutron | Neutral (0) | 1 unit | Inside nucleus |
The three isotopes of hydrogen are:
- Protium (H11)
- Deuterium (H12)
- Tritium (H13)
Valency = 8 (Octet) - 6 (Valence electrons) = 2.
Example: Calcium (Z=20, A=40) and Argon (Z=18, A=40).
2. While revolving in these discrete orbits, the electrons do not radiate energy.
2. An isotope of Iodine is used in the treatment of goitre.
Model: Thomson proposed the atom is a positively charged sphere with electrons embedded in it (like a watermelon or plum pudding).
Postulates: 1) An atom consists of a positively charged sphere and electrons are embedded in it. 2) The negative and positive charges are equal in magnitude, making the atom electrically neutral.
Limitation: It could not explain the results of scattering experiments (like Rutherford's) performed by other scientists.
Observation: While most particles passed through, one out of every 12,000 particles appeared to rebound (deflect by 180°).
Conclusions:
1) Empty Space: Since most particles passed straight through, most space inside the atom is empty.
2) Nucleus: Since very few rebounded, all the positive charge and mass must be concentrated in a tiny volume called the nucleus.
Drawback: Charged particles (electrons) undergoing acceleration in circular orbits should radiate energy. If they radiated energy, they would spiral into the nucleus, making the atom unstable.
Bohr's Solution: Bohr proposed that electrons revolve in discrete orbits and, while in these orbits, they do not radiate energy. This explains why atoms are stable.
Atomic Number (Z): Total number of protons in the nucleus. Defines the element's identity.
Mass Number (A): Sum of protons and neutrons (nucleons).
Example (N714):
Subscript 7 is Z (7 Protons).
Superscript 14 is A (Protons + Neutrons = 14).
= 26.25 + 9.25
= 35.5 u
The mass is not a whole number because it is a weighted average calculated based on the natural abundance ratio of its isotopes. Individual atoms are whole numbers (35 or 37), but the bulk sample averages to 35.5.
Formula: The maximum capacity of a shell is 2n2 (where n is the shell number).
e.g., K-shell (n=1) = 2 electrons; L-shell (n=2) = 8 electrons.
Rules:
1. The outermost shell can accommodate a maximum of 8 electrons.
2. Shells are filled step-wise; electrons do not occupy a new shell unless inner shells are filled.